Metamath Proof Explorer


Theorem ssel

Description: Membership relationships follow from a subclass relationship. (Contributed by NM, 5-Aug-1993) Avoid ax-12 . (Revised by SN, 27-May-2024)

Ref Expression
Assertion ssel ⊢ A ⊆ B → C ∈ A → C ∈ B

Proof

Step Hyp Ref Expression
1 df-ss ⊢ A ⊆ B ↔ ∀ x x ∈ A → x ∈ B
2 id ⊢ x ∈ A → x ∈ B → x ∈ A → x ∈ B
3 2 anim2d ⊢ x ∈ A → x ∈ B → x = C ∧ x ∈ A → x = C ∧ x ∈ B
4 3 aleximi ⊢ ∀ x x ∈ A → x ∈ B → ∃ x x = C ∧ x ∈ A → ∃ x x = C ∧ x ∈ B
5 dfclel ⊢ C ∈ A ↔ ∃ x x = C ∧ x ∈ A
6 dfclel ⊢ C ∈ B ↔ ∃ x x = C ∧ x ∈ B
7 4 5 6 3imtr4g ⊢ ∀ x x ∈ A → x ∈ B → C ∈ A → C ∈ B
8 1 7 sylbi ⊢ A ⊆ B → C ∈ A → C ∈ B