Theorem neqcomd

Description: Commute an inequality. (Contributed by Rohan Ridenour, 3-Aug-2023)

	Ref	Expression
Hypothesis	neqcomd.1	$$⊢\phi \to \neg A=B$$
Assertion	neqcomd	$$⊢\phi \to \neg B=A$$

Proof

Step	Hyp	Ref	Expression
1		neqcomd.1	$$⊢\phi \to \neg A=B$$
2		eqcom	$$⊢A=B\leftrightarrow B=A$$
3	1 2	sylnib	$$⊢\phi \to \neg B=A$$