Metamath Proof Explorer


Theorem eqcom

Description: Commutative law for class equality. Theorem 6.5 of Quine p. 41. (Contributed by NM, 26-May-1993) (Proof shortened by Wolf Lammen, 19-Nov-2019)

Ref Expression
Assertion eqcom ⊢ A = B ↔ B = A

Proof

Step Hyp Ref Expression
1 id ⊢ A = B → A = B
2 1 eqcomd ⊢ A = B → B = A
3 id ⊢ B = A → B = A
4 3 eqcomd ⊢ B = A → A = B
5 2 4 impbii ⊢ A = B ↔ B = A