Metamath Proof Explorer


Theorem nfceqdf

Description: An equality theorem for effectively not free. (Contributed by Mario Carneiro, 14-Oct-2016) Avoid ax-8 and df-clel . (Revised by WL and SN, 23-Aug-2024)

Ref Expression
Hypotheses nfceqdf.1 ⊢ Ⅎ x φ
nfceqdf.2 ⊢ φ → A = B
Assertion nfceqdf ⊢ φ → Ⅎ _ x A ↔ Ⅎ _ x B

Proof

Step Hyp Ref Expression
1 nfceqdf.1 ⊢ Ⅎ x φ
2 nfceqdf.2 ⊢ φ → A = B
3 eleq2w2 ⊢ A = B → y ∈ A ↔ y ∈ B
4 2 3 syl ⊢ φ → y ∈ A ↔ y ∈ B
5 1 4 nfbidf ⊢ φ → Ⅎ x y ∈ A ↔ Ⅎ x y ∈ B
6 5 albidv ⊢ φ → ∀ y Ⅎ x y ∈ A ↔ ∀ y Ⅎ x y ∈ B
7 df-nfc ⊢ Ⅎ _ x A ↔ ∀ y Ⅎ x y ∈ A
8 df-nfc ⊢ Ⅎ _ x B ↔ ∀ y Ⅎ x y ∈ B
9 6 7 8 3bitr4g ⊢ φ → Ⅎ _ x A ↔ Ⅎ _ x B