Metamath Proof Explorer


Theorem nfceqi

Description: Equality theorem for class not-free. (Contributed by Mario Carneiro, 11-Aug-2016) (Proof shortened by Wolf Lammen, 16-Nov-2019) Avoid ax-12 . (Revised by Wolf Lammen, 19-Jun-2023)

Ref Expression
Hypothesis nfceqi.1 ⊢ A = B
Assertion nfceqi ⊢ Ⅎ _ x A ↔ Ⅎ _ x B

Proof

Step Hyp Ref Expression
1 nfceqi.1 ⊢ A = B
2 1 eleq2i ⊢ y ∈ A ↔ y ∈ B
3 2 nfbii ⊢ Ⅎ x y ∈ A ↔ Ⅎ x y ∈ B
4 3 albii ⊢ ∀ y Ⅎ x y ∈ A ↔ ∀ y Ⅎ x y ∈ B
5 df-nfc ⊢ Ⅎ _ x A ↔ ∀ y Ⅎ x y ∈ A
6 df-nfc ⊢ Ⅎ _ x B ↔ ∀ y Ⅎ x y ∈ B
7 4 5 6 3bitr4i ⊢ Ⅎ _ x A ↔ Ⅎ _ x B