Metamath Proof Explorer


Theorem nfntht

Description: Closed form of nfnth . (Contributed by BJ, 16-Sep-2021) (Proof shortened by Wolf Lammen, 4-Sep-2022)

Ref Expression
Assertion nfntht ⊢ ¬ ∃ x φ → Ⅎ x φ

Proof

Step Hyp Ref Expression
1 pm2.21 ⊢ ¬ ∃ x φ → ∃ x φ → ∀ x φ
2 1 nfd ⊢ ¬ ∃ x φ → Ⅎ x φ