Metamath Proof Explorer
		
		
		
		Description:  Closed form of nfnth .  (Contributed by BJ, 16-Sep-2021)  (Proof
     shortened by Wolf Lammen, 4-Sep-2022)
		
			
				
					|  |  | Ref | Expression | 
				
					|  | Assertion | nfntht | ⊢  ( ¬  ∃ 𝑥 𝜑  →  Ⅎ 𝑥 𝜑 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | pm2.21 | ⊢ ( ¬  ∃ 𝑥 𝜑  →  ( ∃ 𝑥 𝜑  →  ∀ 𝑥 𝜑 ) ) | 
						
							| 2 | 1 | nfd | ⊢ ( ¬  ∃ 𝑥 𝜑  →  Ⅎ 𝑥 𝜑 ) |