Metamath Proof Explorer


Theorem nfsbc1d

Description: Deduction version of nfsbc1 . (Contributed by NM, 23-May-2006) (Revised by Mario Carneiro, 12-Oct-2016)

Ref Expression
Hypothesis nfsbc1d.2 ⊢ φ → Ⅎ _ x A
Assertion nfsbc1d ⊢ φ → Ⅎ x [˙A / x]˙ ψ

Proof

Step Hyp Ref Expression
1 nfsbc1d.2 ⊢ φ → Ⅎ _ x A
2 df-sbc ⊢ [˙A / x]˙ ψ ↔ A ∈ x | ψ
3 nfab1 ⊢ Ⅎ _ x x | ψ
4 3 a1i ⊢ φ → Ⅎ _ x x | ψ
5 1 4 nfeld ⊢ φ → Ⅎ x A ∈ x | ψ
6 2 5 nfxfrd ⊢ φ → Ⅎ x [˙A / x]˙ ψ