Metamath Proof Explorer


Theorem nfsbcd

Description: Deduction version of nfsbc . Usage of this theorem is discouraged because it depends on ax-13 . Use the weaker nfsbcdw when possible. (Contributed by NM, 23-Nov-2005) (Revised by Mario Carneiro, 12-Oct-2016) (New usage is discouraged.)

Ref Expression
Hypotheses nfsbcd.1 ⊢ Ⅎ y φ
nfsbcd.2 ⊢ φ → Ⅎ _ x A
nfsbcd.3 ⊢ φ → Ⅎ x ψ
Assertion nfsbcd ⊢ φ → Ⅎ x [˙A / y]˙ ψ

Proof

Step Hyp Ref Expression
1 nfsbcd.1 ⊢ Ⅎ y φ
2 nfsbcd.2 ⊢ φ → Ⅎ _ x A
3 nfsbcd.3 ⊢ φ → Ⅎ x ψ
4 df-sbc ⊢ [˙A / y]˙ ψ ↔ A ∈ y | ψ
5 1 3 nfabd ⊢ φ → Ⅎ _ x y | ψ
6 2 5 nfeld ⊢ φ → Ⅎ x A ∈ y | ψ
7 4 6 nfxfrd ⊢ φ → Ⅎ x [˙A / y]˙ ψ