Metamath Proof Explorer


Theorem nfss

Description: If x is not free in A and B , it is not free in A C_ B . (Contributed by NM, 27-Dec-1996)

Ref Expression
Hypotheses dfssf.1 ⊢ Ⅎ _ x A
dfssf.2 ⊢ Ⅎ _ x B
Assertion nfss ⊢ Ⅎ x A ⊆ B

Proof

Step Hyp Ref Expression
1 dfssf.1 ⊢ Ⅎ _ x A
2 dfssf.2 ⊢ Ⅎ _ x B
3 1 2 dfss3f ⊢ A ⊆ B ↔ ∀ x ∈ A x ∈ B
4 nfra1 ⊢ Ⅎ x ∀ x ∈ A x ∈ B
5 3 4 nfxfr ⊢ Ⅎ x A ⊆ B