Metamath Proof Explorer


Theorem npss0

Description: No set is a proper subset of the empty set. Dual of nvpss . (Contributed by NM, 17-Jun-1998) (Proof shortened by Andrew Salmon, 26-Jun-2011) (Proof shortened by JJ, 14-Jul-2021)

Ref Expression
Assertion npss0 ⊢ ¬ A ⊂ ∅

Proof

Step Hyp Ref Expression
1 0ss ⊢ ∅ ⊆ A
2 ssnpss ⊢ ∅ ⊆ A → ¬ A ⊂ ∅
3 1 2 ax-mp ⊢ ¬ A ⊂ ∅