Metamath Proof Explorer


Theorem nvmid

Description: A vector minus itself is the zero vector. (Contributed by NM, 28-Jan-2008) (New usage is discouraged.)

Ref Expression
Hypotheses nvmeq0.1 ⊢ X = BaseSet ⁡ U
nvmeq0.3 ⊢ M = - v ⁡ U
nvmeq0.5 ⊢ Z = 0 vec ⁡ U
Assertion nvmid ⊢ U ∈ NrmCVec ∧ A ∈ X → A M A = Z

Proof

Step Hyp Ref Expression
1 nvmeq0.1 ⊢ X = BaseSet ⁡ U
2 nvmeq0.3 ⊢ M = - v ⁡ U
3 nvmeq0.5 ⊢ Z = 0 vec ⁡ U
4 eqid ⊢ A = A
5 1 2 3 nvmeq0 ⊢ U ∈ NrmCVec ∧ A ∈ X ∧ A ∈ X → A M A = Z ↔ A = A
6 5 3anidm23 ⊢ U ∈ NrmCVec ∧ A ∈ X → A M A = Z ↔ A = A
7 4 6 mpbiri ⊢ U ∈ NrmCVec ∧ A ∈ X → A M A = Z