Metamath Proof Explorer


Theorem omenps

Description: Omega is equinumerous to a proper subset of itself. Example 13.2(4) of Eisenberg p. 216. (Contributed by NM, 30-Jul-2003)

Ref Expression
Assertion omenps ω ω

Proof

Step Hyp Ref Expression
1 omex ω V
2 limom Lim ω
3 2 limenpsi ω V ω ω
4 1 3 ax-mp ω ω