Metamath Proof Explorer


Theorem oppgtset

Description: Topology of an opposite group. (Contributed by Mario Carneiro, 17-Sep-2015)

Ref Expression
Hypotheses oppgbas.1 ⊢ O = opp 𝑔 ⁡ R
oppgtset.2 ⊢ J = TopSet ⁡ R
Assertion oppgtset ⊢ J = TopSet ⁡ O

Proof

Step Hyp Ref Expression
1 oppgbas.1 ⊢ O = opp 𝑔 ⁡ R
2 oppgtset.2 ⊢ J = TopSet ⁡ R
3 eqid ⊢ + R = + R
4 3 1 oppgval ⊢ O = R sSet + ndx tpos + R
5 tsetid ⊢ TopSet = Slot TopSet ⁡ ndx
6 tsetndxnplusgndx ⊢ TopSet ⁡ ndx ≠ + ndx
7 4 5 6 setsplusg ⊢ TopSet ⁡ R = TopSet ⁡ O
8 2 7 eqtri ⊢ J = TopSet ⁡ O