Metamath Proof Explorer


Theorem orrd

Description: Deduce disjunction from implication. (Contributed by NM, 27-Nov-1995)

Ref Expression
Hypothesis orrd.1 φ¬ψχ
Assertion orrd φψχ

Proof

Step Hyp Ref Expression
1 orrd.1 φ¬ψχ
2 pm2.54 ¬ψχψχ
3 1 2 syl φψχ