Metamath Proof Explorer


Theorem orrd

Description: Deduce disjunction from implication. (Contributed by NM, 27-Nov-1995)

Ref Expression
Hypothesis orrd.1 ⊢ φ → ¬ ψ → χ
Assertion orrd ⊢ φ → ψ ∨ χ

Proof

Step Hyp Ref Expression
1 orrd.1 ⊢ φ → ¬ ψ → χ
2 pm2.54 ⊢ ¬ ψ → χ → ψ ∨ χ
3 1 2 syl ⊢ φ → ψ ∨ χ