Metamath Proof Explorer


Theorem par2hom

Description: The four hom-sets of the explicit two-object parallel-arrow category. (Contributed by Zhi Wang, 14-Sep-2026)

Ref Expression
Hypothesis par2hom.h ⊢ H = m ∈ 2 𝑜 , n ∈ 2 𝑜 ⟼ if m = n 2 𝑜 if m = ∅ ∧ n = 1 𝑜 2 𝑜 ∅
Assertion par2hom ⊢ ∅ H ∅ = 2 𝑜 ∧ 1 𝑜 H 1 𝑜 = 2 𝑜 ∧ ∅ H 1 𝑜 = 2 𝑜 ∧ 1 𝑜 H ∅ = ∅

Proof

Step Hyp Ref Expression
1 par2hom.h ⊢ H = m ∈ 2 𝑜 , n ∈ 2 𝑜 ⟼ if m = n 2 𝑜 if m = ∅ ∧ n = 1 𝑜 2 𝑜 ∅
2 0ex ⊢ ∅ ∈ V
3 2 prid1 ⊢ ∅ ∈ ∅ 1 𝑜
4 df2o3 ⊢ 2 𝑜 = ∅ 1 𝑜
5 3 4 eleqtrri ⊢ ∅ ∈ 2 𝑜
6 2oex ⊢ 2 𝑜 ∈ V
7 1 6 parhomval ⊢ ∅ ∈ 2 𝑜 ∧ ∅ ∈ 2 𝑜 → ∅ H ∅ = if ∅ = ∅ 2 𝑜 if ∅ = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅
8 5 5 7 mp2an ⊢ ∅ H ∅ = if ∅ = ∅ 2 𝑜 if ∅ = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅
9 eqid ⊢ ∅ = ∅
10 9 iftruei ⊢ if ∅ = ∅ 2 𝑜 if ∅ = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅ = 2 𝑜
11 8 10 eqtri ⊢ ∅ H ∅ = 2 𝑜
12 1oelpr ⊢ 1 𝑜 ∈ ∅ 1 𝑜
13 12 4 eleqtrri ⊢ 1 𝑜 ∈ 2 𝑜
14 1 6 parhomval ⊢ 1 𝑜 ∈ 2 𝑜 ∧ 1 𝑜 ∈ 2 𝑜 → 1 𝑜 H 1 𝑜 = if 1 𝑜 = 1 𝑜 2 𝑜 if 1 𝑜 = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅
15 13 13 14 mp2an ⊢ 1 𝑜 H 1 𝑜 = if 1 𝑜 = 1 𝑜 2 𝑜 if 1 𝑜 = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅
16 eqid ⊢ 1 𝑜 = 1 𝑜
17 16 iftruei ⊢ if 1 𝑜 = 1 𝑜 2 𝑜 if 1 𝑜 = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅ = 2 𝑜
18 15 17 eqtri ⊢ 1 𝑜 H 1 𝑜 = 2 𝑜
19 1 6 parhomval ⊢ ∅ ∈ 2 𝑜 ∧ 1 𝑜 ∈ 2 𝑜 → ∅ H 1 𝑜 = if ∅ = 1 𝑜 2 𝑜 if ∅ = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅
20 5 13 19 mp2an ⊢ ∅ H 1 𝑜 = if ∅ = 1 𝑜 2 𝑜 if ∅ = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅
21 1n0 ⊢ 1 𝑜 ≠ ∅
22 21 nesymi ⊢ ¬ ∅ = 1 𝑜
23 22 iffalsei ⊢ if ∅ = 1 𝑜 2 𝑜 if ∅ = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅ = if ∅ = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅
24 9 16 pm3.2i ⊢ ∅ = ∅ ∧ 1 𝑜 = 1 𝑜
25 24 iftruei ⊢ if ∅ = ∅ ∧ 1 𝑜 = 1 𝑜 2 𝑜 ∅ = 2 𝑜
26 20 23 25 3eqtri ⊢ ∅ H 1 𝑜 = 2 𝑜
27 1 6 parhomval ⊢ 1 𝑜 ∈ 2 𝑜 ∧ ∅ ∈ 2 𝑜 → 1 𝑜 H ∅ = if 1 𝑜 = ∅ 2 𝑜 if 1 𝑜 = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅
28 13 5 27 mp2an ⊢ 1 𝑜 H ∅ = if 1 𝑜 = ∅ 2 𝑜 if 1 𝑜 = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅
29 21 neii ⊢ ¬ 1 𝑜 = ∅
30 29 iffalsei ⊢ if 1 𝑜 = ∅ 2 𝑜 if 1 𝑜 = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅ = if 1 𝑜 = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅
31 29 intnanr ⊢ ¬ 1 𝑜 = ∅ ∧ ∅ = 1 𝑜
32 31 iffalsei ⊢ if 1 𝑜 = ∅ ∧ ∅ = 1 𝑜 2 𝑜 ∅ = ∅
33 28 30 32 3eqtri ⊢ 1 𝑜 H ∅ = ∅
34 26 33 pm3.2i ⊢ ∅ H 1 𝑜 = 2 𝑜 ∧ 1 𝑜 H ∅ = ∅
35 11 18 34 3pm3.2i ⊢ ∅ H ∅ = 2 𝑜 ∧ 1 𝑜 H 1 𝑜 = 2 𝑜 ∧ ∅ H 1 𝑜 = 2 𝑜 ∧ 1 𝑜 H ∅ = ∅