Metamath Proof Explorer


Theorem nesymi

Description: Inference associated with nesym . (Contributed by BJ, 7-Jul-2018) (Proof shortened by Wolf Lammen, 25-Nov-2019)

Ref Expression
Hypothesis nesymi.1 ⊢ A ≠ B
Assertion nesymi ⊢ ¬ B = A

Proof

Step Hyp Ref Expression
1 nesymi.1 ⊢ A ≠ B
2 1 necomi ⊢ B ≠ A
3 2 neii ⊢ ¬ B = A