Metamath Proof Explorer


Theorem nesymi

Description: Inference associated with nesym . (Contributed by BJ, 7-Jul-2018) (Proof shortened by Wolf Lammen, 25-Nov-2019)

Ref Expression
Hypothesis nesymi.1 ⊢ 𝐴 ≠ 𝐵
Assertion nesymi ¬ 𝐵 = 𝐴

Proof

Step Hyp Ref Expression
1 nesymi.1 ⊢ 𝐴 ≠ 𝐵
2 1 necomi ⊢ 𝐵 ≠ 𝐴
3 2 neii ⊢ ¬ 𝐵 = 𝐴