Metamath Proof Explorer


Theorem pjsubii

Description: Projection of vector difference is difference of projections. (Contributed by NM, 31-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses pjidm.1 ⊢ H ∈ C ℋ
pjidm.2 ⊢ A ∈ ℋ
pjsub.3 ⊢ B ∈ ℋ
Assertion pjsubii ⊢ proj ℎ ⁡ H ⁡ A - ℎ B = proj ℎ ⁡ H ⁡ A - ℎ proj ℎ ⁡ H ⁡ B

Proof

Step Hyp Ref Expression
1 pjidm.1 ⊢ H ∈ C ℋ
2 pjidm.2 ⊢ A ∈ ℋ
3 pjsub.3 ⊢ B ∈ ℋ
4 neg1cn ⊢ − 1 ∈ ℂ
5 4 3 hvmulcli ⊢ -1 ⋅ ℎ B ∈ ℋ
6 1 2 5 pjaddii ⊢ proj ℎ ⁡ H ⁡ A + ℎ -1 ⋅ ℎ B = proj ℎ ⁡ H ⁡ A + ℎ proj ℎ ⁡ H ⁡ -1 ⋅ ℎ B
7 1 3 4 pjmulii ⊢ proj ℎ ⁡ H ⁡ -1 ⋅ ℎ B = -1 ⋅ ℎ proj ℎ ⁡ H ⁡ B
8 7 oveq2i ⊢ proj ℎ ⁡ H ⁡ A + ℎ proj ℎ ⁡ H ⁡ -1 ⋅ ℎ B = proj ℎ ⁡ H ⁡ A + ℎ -1 ⋅ ℎ proj ℎ ⁡ H ⁡ B
9 6 8 eqtri ⊢ proj ℎ ⁡ H ⁡ A + ℎ -1 ⋅ ℎ B = proj ℎ ⁡ H ⁡ A + ℎ -1 ⋅ ℎ proj ℎ ⁡ H ⁡ B
10 2 3 hvsubvali ⊢ A - ℎ B = A + ℎ -1 ⋅ ℎ B
11 10 fveq2i ⊢ proj ℎ ⁡ H ⁡ A - ℎ B = proj ℎ ⁡ H ⁡ A + ℎ -1 ⋅ ℎ B
12 1 2 pjhclii ⊢ proj ℎ ⁡ H ⁡ A ∈ ℋ
13 1 3 pjhclii ⊢ proj ℎ ⁡ H ⁡ B ∈ ℋ
14 12 13 hvsubvali ⊢ proj ℎ ⁡ H ⁡ A - ℎ proj ℎ ⁡ H ⁡ B = proj ℎ ⁡ H ⁡ A + ℎ -1 ⋅ ℎ proj ℎ ⁡ H ⁡ B
15 9 11 14 3eqtr4i ⊢ proj ℎ ⁡ H ⁡ A - ℎ B = proj ℎ ⁡ H ⁡ A - ℎ proj ℎ ⁡ H ⁡ B