Metamath Proof Explorer


Theorem pm13.195

Description: Theorem *13.195 in WhiteheadRussell p. 179. This theorem is very similar to sbc5 . (Contributed by Andrew Salmon, 3-Jun-2011) (Revised by NM, 4-Jan-2017)

Ref Expression
Assertion pm13.195 y y = A φ [˙A / y]˙ φ

Proof

Step Hyp Ref Expression
1 sbc5 [˙A / y]˙ φ y y = A φ
2 1 bicomi y y = A φ [˙A / y]˙ φ