Metamath Proof Explorer


Theorem predeq1

Description: Equality theorem for the predecessor class. (Contributed by Scott Fenton, 2-Feb-2011)

Ref Expression
Assertion predeq1 ⊢ R = S → Pred R A X = Pred S A X

Proof

Step Hyp Ref Expression
1 eqid ⊢ A = A
2 eqid ⊢ X = X
3 predeq123 ⊢ R = S ∧ A = A ∧ X = X → Pred R A X = Pred S A X
4 1 2 3 mp3an23 ⊢ R = S → Pred R A X = Pred S A X