Metamath Proof Explorer


Theorem predin

Description: Intersection law for predecessor classes. (Contributed by Scott Fenton, 29-Mar-2011)

Ref Expression
Assertion predin ⊢ Pred R A ∩ B X = Pred R A X ∩ Pred R B X

Proof

Step Hyp Ref Expression
1 inindir ⊢ A ∩ B ∩ R -1 X = A ∩ R -1 X ∩ B ∩ R -1 X
2 df-pred ⊢ Pred R A ∩ B X = A ∩ B ∩ R -1 X
3 df-pred ⊢ Pred R A X = A ∩ R -1 X
4 df-pred ⊢ Pred R B X = B ∩ R -1 X
5 3 4 ineq12i ⊢ Pred R A X ∩ Pred R B X = A ∩ R -1 X ∩ B ∩ R -1 X
6 1 2 5 3eqtr4i ⊢ Pred R A ∩ B X = Pred R A X ∩ Pred R B X