Metamath Proof Explorer


Theorem prlngeq

Description: Playfair's axiom, written as an equality: if two different lines are parallel to a given line at a given point, they are equal. (Contributed by Thierry Arnoux, 20-Jul-2026)

Ref Expression
Hypotheses prlngeq.p ⊢ P = Base G
prlngeq.r No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
prlngeq.g ⊢ φ → G ∈ 𝒢 Tarski
prlngeq.1 ⊢ φ → G ∈ 𝒢 Tarski E
prlngeq.b ⊢ φ → A ∥ ˙ B
prlngeq.c ⊢ φ → A ∥ ˙ C
prlngeq.2 ⊢ φ → X ∈ B
prlngeq.3 ⊢ φ → X ∈ C
Assertion prlngeq ⊢ φ → B = C

Proof

Step Hyp Ref Expression
1 prlngeq.p ⊢ P = Base G
2 prlngeq.r Could not format .|| = ( parlnG ` G ) : No typesetting found for |- .|| = ( parlnG ` G ) with typecode |-
3 prlngeq.g ⊢ φ → G ∈ 𝒢 Tarski
4 prlngeq.1 ⊢ φ → G ∈ 𝒢 Tarski E
5 prlngeq.b ⊢ φ → A ∥ ˙ B
6 prlngeq.c ⊢ φ → A ∥ ˙ C
7 prlngeq.2 ⊢ φ → X ∈ B
8 prlngeq.3 ⊢ φ → X ∈ C
9 eqid ⊢ Line 𝒢 ⁡ G = Line 𝒢 ⁡ G
10 9 2 3 5 prlngrcl1 ⊢ φ → A ∈ ran ⁡ Line 𝒢 ⁡ G
11 eqid ⊢ Itv ⁡ G = Itv ⁡ G
12 9 2 3 5 prlngrcl2 ⊢ φ → B ∈ ran ⁡ Line 𝒢 ⁡ G
13 1 9 11 3 12 7 tglnpt ⊢ φ → X ∈ P
14 1 9 2 3 10 13 4 prlngmo2 ⊢ φ → ∃* b ∈ ran ⁡ Line 𝒢 ⁡ G A ∥ ˙ b ∧ X ∈ b
15 5 7 jca ⊢ φ → A ∥ ˙ B ∧ X ∈ B
16 9 2 3 6 prlngrcl2 ⊢ φ → C ∈ ran ⁡ Line 𝒢 ⁡ G
17 6 8 jca ⊢ φ → A ∥ ˙ C ∧ X ∈ C
18 breq2 ⊢ b = B → A ∥ ˙ b ↔ A ∥ ˙ B
19 eleq2 ⊢ b = B → X ∈ b ↔ X ∈ B
20 18 19 anbi12d ⊢ b = B → A ∥ ˙ b ∧ X ∈ b ↔ A ∥ ˙ B ∧ X ∈ B
21 breq2 ⊢ b = C → A ∥ ˙ b ↔ A ∥ ˙ C
22 eleq2 ⊢ b = C → X ∈ b ↔ X ∈ C
23 21 22 anbi12d ⊢ b = C → A ∥ ˙ b ∧ X ∈ b ↔ A ∥ ˙ C ∧ X ∈ C
24 20 23 rmoi ⊢ ∃* b ∈ ran ⁡ Line 𝒢 ⁡ G A ∥ ˙ b ∧ X ∈ b ∧ B ∈ ran ⁡ Line 𝒢 ⁡ G ∧ A ∥ ˙ B ∧ X ∈ B ∧ C ∈ ran ⁡ Line 𝒢 ⁡ G ∧ A ∥ ˙ C ∧ X ∈ C → B = C
25 14 12 15 16 17 24 syl122anc ⊢ φ → B = C