Metamath Proof Explorer


Theorem prodeq2ad

Description: Equality deduction for product. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypothesis prodeq2ad.1 φ B = C
Assertion prodeq2ad φ k A B = k A C

Proof

Step Hyp Ref Expression
1 prodeq2ad.1 φ B = C
2 1 ralrimivw φ k A B = C
3 2 prodeq2d φ k A B = k A C