Metamath Proof Explorer


Theorem prodeq2ad

Description: Equality deduction for product. (Contributed by Glauco Siliprandi, 5-Apr-2020)

Ref Expression
Hypothesis prodeq2ad.1 ⊢ φ → B = C
Assertion prodeq2ad ⊢ φ → ∏ k ∈ A B = ∏ k ∈ A C

Proof

Step Hyp Ref Expression
1 prodeq2ad.1 ⊢ φ → B = C
2 1 ralrimivw ⊢ φ → ∀ k ∈ A B = C
3 2 prodeq2d ⊢ φ → ∏ k ∈ A B = ∏ k ∈ A C