Metamath Proof Explorer


Theorem pssssd

Description: Deduce subclass from proper subclass. (Contributed by NM, 29-Feb-1996)

Ref Expression
Hypothesis pssssd.1 ⊢ φ → A ⊂ B
Assertion pssssd ⊢ φ → A ⊆ B

Proof

Step Hyp Ref Expression
1 pssssd.1 ⊢ φ → A ⊂ B
2 pssss ⊢ A ⊂ B → A ⊆ B
3 1 2 syl ⊢ φ → A ⊆ B