Metamath Proof Explorer


Theorem pssssd

Description: Deduce subclass from proper subclass. (Contributed by NM, 29-Feb-1996)

Ref Expression
Hypothesis pssssd.1 φ A B
Assertion pssssd φ A B

Proof

Step Hyp Ref Expression
1 pssssd.1 φ A B
2 pssss A B A B
3 1 2 syl φ A B