Metamath Proof Explorer


Theorem pweqd

Description: Equality deduction for power class. (Contributed by NM, 27-Nov-2013)

Ref Expression
Hypothesis pweqd.1 ⊢ φ → A = B
Assertion pweqd ⊢ φ → 𝒫 A = 𝒫 B

Proof

Step Hyp Ref Expression
1 pweqd.1 ⊢ φ → A = B
2 pweq ⊢ A = B → 𝒫 A = 𝒫 B
3 1 2 syl ⊢ φ → 𝒫 A = 𝒫 B