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r1sssucd
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Metamath Proof Explorer
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Theorem
r1sssucd
Description:
Deductive form of
r1sssuc
.
(Contributed by
Noam Pasman
, 19-Jan-2025)
Ref
Expression
Hypothesis
r1sssucd.1
⊢
φ
→
A
∈
On
Assertion
r1sssucd
⊢
φ
→
R
1
A
⊆
R
1
suc
A
Proof
Step
Hyp
Ref
Expression
1
r1sssucd.1
⊢
φ
→
A
∈
On
2
r1sssuc
⊢
A
∈
On
→
R
1
A
⊆
R
1
suc
A
3
1
2
syl
⊢
φ
→
R
1
A
⊆
R
1
suc
A