Metamath Proof Explorer


Theorem r1sssucd

Description: Deductive form of r1sssuc . (Contributed by Noam Pasman, 19-Jan-2025)

Ref Expression
Hypothesis r1sssucd.1 φ A On
Assertion r1sssucd φ R1 A R1 suc A

Proof

Step Hyp Ref Expression
1 r1sssucd.1 φ A On
2 r1sssuc A On R1 A R1 suc A
3 1 2 syl φ R1 A R1 suc A