Metamath Proof Explorer


Theorem reccl

Description: Closure law for reciprocal. (Contributed by NM, 30-Apr-2005)

Ref Expression
Assertion reccl ⊢ A ∈ ℂ ∧ A ≠ 0 → 1 A ∈ ℂ

Proof

Step Hyp Ref Expression
1 ax-1cn ⊢ 1 ∈ ℂ
2 divcl ⊢ 1 ∈ ℂ ∧ A ∈ ℂ ∧ A ≠ 0 → 1 A ∈ ℂ
3 1 2 mp3an1 ⊢ A ∈ ℂ ∧ A ≠ 0 → 1 A ∈ ℂ