Metamath Proof Explorer


Theorem recseq

Description: Equality theorem for recs . (Contributed by Stefan O'Rear, 18-Jan-2015)

Ref Expression
Assertion recseq ⊢ F = G → recs ⁡ F = recs ⁡ G

Proof

Step Hyp Ref Expression
1 wrecseq3 ⊢ F = G → wrecs ⁡ E On F = wrecs ⁡ E On G
2 df-recs ⊢ recs ⁡ F = wrecs ⁡ E On F
3 df-recs ⊢ recs ⁡ G = wrecs ⁡ E On G
4 1 2 3 3eqtr4g ⊢ F = G → recs ⁡ F = recs ⁡ G