Metamath Proof Explorer


Theorem redivcan3d

Description: A cancellation law for division. (Contributed by SN, 25-Nov-2025)

Ref Expression
Hypotheses redivcan2d.a φ A
redivcan2d.b φ B
redivcan2d.z φ B 0
Assertion redivcan3d φ B A / B = A

Proof

Step Hyp Ref Expression
1 redivcan2d.a φ A
2 redivcan2d.b φ B
3 redivcan2d.z φ B 0
4 eqidd φ B A = B A
5 2 1 remulcld φ B A
6 5 1 2 3 redivmuld φ B A / B = A B A = B A
7 4 6 mpbird φ B A / B = A