Metamath Proof Explorer


Theorem redivmuld

Description: Relationship between division and multiplication. (Contributed by SN, 25-Nov-2025)

Ref Expression
Hypotheses redivmuld.a φ A
redivmuld.b φ B
redivmuld.c φ C
redivmuld.z φ C 0
Assertion redivmuld φ A / C = B C B = A

Proof

Step Hyp Ref Expression
1 redivmuld.a φ A
2 redivmuld.b φ B
3 redivmuld.c φ C
4 redivmuld.z φ C 0
5 1 3 4 redivvald φ A / C = ι x | C x = A
6 5 eqeq1d φ A / C = B ι x | C x = A = B
7 1 3 4 rediveud φ ∃! x C x = A
8 oveq2 x = B C x = C B
9 8 eqeq1d x = B C x = A C B = A
10 9 riota2 B ∃! x C x = A C B = A ι x | C x = A = B
11 2 7 10 syl2anc φ C B = A ι x | C x = A = B
12 6 11 bitr4d φ A / C = B C B = A