Metamath Proof Explorer


Theorem redivmul2d

Description: Relationship between division and multiplication. (Contributed by SN, 2-Apr-2026)

Ref Expression
Hypotheses redivmuld.a ⊢ φ → A ∈ ℝ
redivmuld.b ⊢ φ → B ∈ ℝ
redivmuld.c ⊢ φ → C ∈ ℝ
redivmuld.z ⊢ φ → C ≠ 0
Assertion redivmul2d ⊢ φ → A / ℝ C = B ↔ A = C ⁢ B

Proof

Step Hyp Ref Expression
1 redivmuld.a ⊢ φ → A ∈ ℝ
2 redivmuld.b ⊢ φ → B ∈ ℝ
3 redivmuld.c ⊢ φ → C ∈ ℝ
4 redivmuld.z ⊢ φ → C ≠ 0
5 1 2 3 4 redivmuld ⊢ φ → A / ℝ C = B ↔ C ⁢ B = A
6 eqcom ⊢ C ⁢ B = A ↔ A = C ⁢ B
7 5 6 bitrdi ⊢ φ → A / ℝ C = B ↔ A = C ⁢ B