Metamath Proof Explorer


Theorem redivmul2d

Description: Relationship between division and multiplication. (Contributed by SN, 2-Apr-2026)

Ref Expression
Hypotheses redivmuld.a
|- ( ph -> A e. RR )
redivmuld.b
|- ( ph -> B e. RR )
redivmuld.c
|- ( ph -> C e. RR )
redivmuld.z
|- ( ph -> C =/= 0 )
Assertion redivmul2d
|- ( ph -> ( ( A /R C ) = B <-> A = ( C x. B ) ) )

Proof

Step Hyp Ref Expression
1 redivmuld.a
 |-  ( ph -> A e. RR )
2 redivmuld.b
 |-  ( ph -> B e. RR )
3 redivmuld.c
 |-  ( ph -> C e. RR )
4 redivmuld.z
 |-  ( ph -> C =/= 0 )
5 1 2 3 4 redivmuld
 |-  ( ph -> ( ( A /R C ) = B <-> ( C x. B ) = A ) )
6 eqcom
 |-  ( ( C x. B ) = A <-> A = ( C x. B ) )
7 5 6 bitrdi
 |-  ( ph -> ( ( A /R C ) = B <-> A = ( C x. B ) ) )