Metamath Proof Explorer


Theorem redivmul2d

Description: Relationship between division and multiplication. (Contributed by SN, 2-Apr-2026)

Ref Expression
Hypotheses redivmuld.a ( 𝜑𝐴 ∈ ℝ )
redivmuld.b ( 𝜑𝐵 ∈ ℝ )
redivmuld.c ( 𝜑𝐶 ∈ ℝ )
redivmuld.z ( 𝜑𝐶 ≠ 0 )
Assertion redivmul2d ( 𝜑 → ( ( 𝐴 / 𝐶 ) = 𝐵𝐴 = ( 𝐶 · 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 redivmuld.a ( 𝜑𝐴 ∈ ℝ )
2 redivmuld.b ( 𝜑𝐵 ∈ ℝ )
3 redivmuld.c ( 𝜑𝐶 ∈ ℝ )
4 redivmuld.z ( 𝜑𝐶 ≠ 0 )
5 1 2 3 4 redivmuld ( 𝜑 → ( ( 𝐴 / 𝐶 ) = 𝐵 ↔ ( 𝐶 · 𝐵 ) = 𝐴 ) )
6 eqcom ( ( 𝐶 · 𝐵 ) = 𝐴𝐴 = ( 𝐶 · 𝐵 ) )
7 5 6 bitrdi ( 𝜑 → ( ( 𝐴 / 𝐶 ) = 𝐵𝐴 = ( 𝐶 · 𝐵 ) ) )