Metamath Proof Explorer


Theorem redivmul2d

Description: Relationship between division and multiplication. (Contributed by SN, 2-Apr-2026)

Ref Expression
Hypotheses redivmuld.a ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
redivmuld.b ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
redivmuld.c ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
redivmuld.z ⊢ ( 𝜑 → 𝐶 ≠ 0 )
Assertion redivmul2d ( 𝜑 → ( ( 𝐴 /ℝ 𝐶 ) = 𝐵 ↔ 𝐴 = ( 𝐶 · 𝐵 ) ) )

Proof

Step Hyp Ref Expression
1 redivmuld.a ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 redivmuld.b ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
3 redivmuld.c ⊢ ( 𝜑 → 𝐶 ∈ ℝ )
4 redivmuld.z ⊢ ( 𝜑 → 𝐶 ≠ 0 )
5 1 2 3 4 redivmuld ⊢ ( 𝜑 → ( ( 𝐴 /ℝ 𝐶 ) = 𝐵 ↔ ( 𝐶 · 𝐵 ) = 𝐴 ) )
6 eqcom ⊢ ( ( 𝐶 · 𝐵 ) = 𝐴 ↔ 𝐴 = ( 𝐶 · 𝐵 ) )
7 5 6 bitrdi ⊢ ( 𝜑 → ( ( 𝐴 /ℝ 𝐶 ) = 𝐵 ↔ 𝐴 = ( 𝐶 · 𝐵 ) ) )