Metamath Proof Explorer


Theorem redivcan2d

Description: A cancellation law for division. (Contributed by SN, 25-Nov-2025)

Ref Expression
Hypotheses redivcan2d.a φ A
redivcan2d.b φ B
redivcan2d.z φ B 0
Assertion redivcan2d φ B A / B = A

Proof

Step Hyp Ref Expression
1 redivcan2d.a φ A
2 redivcan2d.b φ B
3 redivcan2d.z φ B 0
4 eqidd φ A / B = A / B
5 1 2 3 sn-redivcld φ A / B
6 1 5 2 3 redivmuld φ A / B = A / B B A / B = A
7 4 6 mpbid φ B A / B = A