Metamath Proof Explorer


Theorem redivvald

Description: Value of real division, which is the (unique) real x such that ( B x. x ) = A . (Contributed by SN, 25-Nov-2025)

Ref Expression
Hypotheses redivvald.a ⊢ φ → A ∈ ℝ
redivvald.b ⊢ φ → B ∈ ℝ
redivvald.z ⊢ φ → B ≠ 0
Assertion redivvald ⊢ φ → A / ℝ B = ι x ∈ ℝ | B ⁢ x = A

Proof

Step Hyp Ref Expression
1 redivvald.a ⊢ φ → A ∈ ℝ
2 redivvald.b ⊢ φ → B ∈ ℝ
3 redivvald.z ⊢ φ → B ≠ 0
4 2 3 eldifsnd ⊢ φ → B ∈ ℝ ∖ 0
5 eqeq2 ⊢ z = A → y ⁢ x = z ↔ y ⁢ x = A
6 5 riotabidv ⊢ z = A → ι x ∈ ℝ | y ⁢ x = z = ι x ∈ ℝ | y ⁢ x = A
7 oveq1 ⊢ y = B → y ⁢ x = B ⁢ x
8 7 eqeq1d ⊢ y = B → y ⁢ x = A ↔ B ⁢ x = A
9 8 riotabidv ⊢ y = B → ι x ∈ ℝ | y ⁢ x = A = ι x ∈ ℝ | B ⁢ x = A
10 df-rediv ⊢ / ℝ = z ∈ ℝ , y ∈ ℝ ∖ 0 ⟼ ι x ∈ ℝ | y ⁢ x = z
11 riotaex ⊢ ι x ∈ ℝ | B ⁢ x = A ∈ V
12 6 9 10 11 ovmpo ⊢ A ∈ ℝ ∧ B ∈ ℝ ∖ 0 → A / ℝ B = ι x ∈ ℝ | B ⁢ x = A
13 1 4 12 syl2anc ⊢ φ → A / ℝ B = ι x ∈ ℝ | B ⁢ x = A