Metamath Proof Explorer


Theorem renegd

Description: Real part of negative. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis recld.1 ⊢ φ → A ∈ ℂ
Assertion renegd ⊢ φ → ℜ ⁡ − A = − ℜ ⁡ A

Proof

Step Hyp Ref Expression
1 recld.1 ⊢ φ → A ∈ ℂ
2 reneg ⊢ A ∈ ℂ → ℜ ⁡ − A = − ℜ ⁡ A
3 1 2 syl ⊢ φ → ℜ ⁡ − A = − ℜ ⁡ A