Metamath Proof Explorer


Theorem renegd

Description: Real part of negative. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypothesis recld.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
Assertion renegd ( 𝜑 → ( ℜ ‘ - 𝐴 ) = - ( ℜ ‘ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 recld.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 reneg ⊢ ( 𝐴 ∈ ℂ → ( ℜ ‘ - 𝐴 ) = - ( ℜ ‘ 𝐴 ) )
3 1 2 syl ⊢ ( 𝜑 → ( ℜ ‘ - 𝐴 ) = - ( ℜ ‘ 𝐴 ) )