Metamath Proof Explorer


Theorem reutruALT

Description: Alternate proof of reutru . (Contributed by Zhi Wang, 23-Sep-2024) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion reutruALT ⊢ ∃! x x ∈ A ↔ ∃! x ∈ A ⊤

Proof

Step Hyp Ref Expression
1 rextru ⊢ ∃ x x ∈ A ↔ ∃ x ∈ A ⊤
2 rmotru ⊢ ∃* x x ∈ A ↔ ∃* x ∈ A ⊤
3 1 2 anbi12i ⊢ ∃ x x ∈ A ∧ ∃* x x ∈ A ↔ ∃ x ∈ A ⊤ ∧ ∃* x ∈ A ⊤
4 df-eu ⊢ ∃! x x ∈ A ↔ ∃ x x ∈ A ∧ ∃* x x ∈ A
5 reu5 ⊢ ∃! x ∈ A ⊤ ↔ ∃ x ∈ A ⊤ ∧ ∃* x ∈ A ⊤
6 3 4 5 3bitr4i ⊢ ∃! x x ∈ A ↔ ∃! x ∈ A ⊤