Metamath Proof Explorer


Theorem reutru

Description: Two ways of expressing "exactly one" element. (Contributed by Zhi Wang, 23-Sep-2024)

Ref Expression
Assertion reutru ⊢ ∃! x x ∈ A ↔ ∃! x ∈ A ⊤

Proof

Step Hyp Ref Expression
1 tru ⊢ ⊤
2 1 biantru ⊢ x ∈ A ↔ x ∈ A ∧ ⊤
3 2 eubii ⊢ ∃! x x ∈ A ↔ ∃! x x ∈ A ∧ ⊤
4 df-reu ⊢ ∃! x ∈ A ⊤ ↔ ∃! x x ∈ A ∧ ⊤
5 3 4 bitr4i ⊢ ∃! x x ∈ A ↔ ∃! x ∈ A ⊤