Metamath Proof Explorer


Theorem rhmsub

Description: Ring homomorphisms preserve subtraction. (Contributed by Jeff Madsen, 15-Jun-2011) (Revised by AV, 10-Jan-2025)

Ref Expression
Hypotheses rhmsub.x ⊢ X = Base R
rhmsub.m ⊢ - ˙ = - R
rhmsub.n ⊢ N = - S
Assertion rhmsub ⊢ F ∈ R RingHom S ∧ A ∈ X ∧ B ∈ X → F ⁡ A - ˙ B = F ⁡ A N F ⁡ B

Proof

Step Hyp Ref Expression
1 rhmsub.x ⊢ X = Base R
2 rhmsub.m ⊢ - ˙ = - R
3 rhmsub.n ⊢ N = - S
4 rhmghm ⊢ F ∈ R RingHom S → F ∈ R GrpHom S
5 1 2 3 ghmsub ⊢ F ∈ R GrpHom S ∧ A ∈ X ∧ B ∈ X → F ⁡ A - ˙ B = F ⁡ A N F ⁡ B
6 4 5 syl3an1 ⊢ F ∈ R RingHom S ∧ A ∈ X ∧ B ∈ X → F ⁡ A - ˙ B = F ⁡ A N F ⁡ B