Metamath Proof Explorer

Theorem risc

Description: Obsolete theorem, use brric2 instead. The ring isomorphism relation. (Contributed by Jeff Madsen, 16-Jun-2011) (Proof modification is discouraged.) (New usage is discouraged.)

		Ref	Expression
	Assertion	risc	$⊢ (R \in RingOps \land S \in RingOps) \to (R ≃_{𝑟} S \leftrightarrow \exists f f \in (R RingOpsIso S))$

Proof

Step	Hyp	Ref	Expression
1		isriscg	$⊢ (R \in RingOps \land S \in RingOps) \to (R ≃_{𝑟} S \leftrightarrow ((R \in RingOps \land S \in RingOps) \land \exists f f \in (R RingOpsIso S)))$
2	1	bianabs	$⊢ (R \in RingOps \land S \in RingOps) \to (R ≃_{𝑟} S \leftrightarrow \exists f f \in (R RingOpsIso S))$