Metamath Proof Explorer


Theorem brric2

Description: The ring isomorphism relation. (Contributed by Jeff Madsen, 16-Jun-2011) (Revised by AV, 23-Jul-2026)

Ref Expression
Assertion brric2 ⊢ R ∈ Ring ∧ S ∈ Ring → R ≃ 𝑟 S ↔ ∃ f f ∈ R RingIso S

Proof

Step Hyp Ref Expression
1 isbrric2 ⊢ R ≃ 𝑟 S ↔ R ∈ Ring ∧ S ∈ Ring ∧ ∃ f f ∈ R RingIso S
2 1 baib ⊢ R ∈ Ring ∧ S ∈ Ring → R ≃ 𝑟 S ↔ ∃ f f ∈ R RingIso S