Metamath Proof Explorer


Theorem brric2

Description: The ring isomorphism relation. (Contributed by Jeff Madsen, 16-Jun-2011) (Revised by AV, 23-Jul-2026)

Ref Expression
Assertion brric2 ( ( 𝑅 ∈ Ring ∧ 𝑆 ∈ Ring ) → ( 𝑅𝑟 𝑆 ↔ ∃ 𝑓 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) ) )

Proof

Step Hyp Ref Expression
1 isbrric2 ( 𝑅𝑟 𝑆 ↔ ( ( 𝑅 ∈ Ring ∧ 𝑆 ∈ Ring ) ∧ ∃ 𝑓 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) ) )
2 1 baib ( ( 𝑅 ∈ Ring ∧ 𝑆 ∈ Ring ) → ( 𝑅𝑟 𝑆 ↔ ∃ 𝑓 𝑓 ∈ ( 𝑅 RingIso 𝑆 ) ) )