Metamath Proof Explorer


Theorem simplbi

Description: Deduction eliminating a conjunct. (Contributed by NM, 27-May-1998)

Ref Expression
Hypothesis simplbi.1 ⊢ ( 𝜑 ↔ ( 𝜓 ∧ 𝜒 ) )
Assertion simplbi ( 𝜑 → 𝜓 )

Proof

Step Hyp Ref Expression
1 simplbi.1 ⊢ ( 𝜑 ↔ ( 𝜓 ∧ 𝜒 ) )
2 1 biimpi ⊢ ( 𝜑 → ( 𝜓 ∧ 𝜒 ) )
3 2 simpld ⊢ ( 𝜑 → 𝜓 )