Metamath Proof Explorer


Theorem rngimrnghm

Description: An isomorphism of non-unital rings is a homomorphism. (Contributed by AV, 23-Feb-2020)

Ref Expression
Hypotheses rnghmf1o.b ⊢ B = Base R
rnghmf1o.c ⊢ C = Base S
Assertion rngimrnghm ⊢ F ∈ R RngIso S → F ∈ R RngHom S

Proof

Step Hyp Ref Expression
1 rnghmf1o.b ⊢ B = Base R
2 rnghmf1o.c ⊢ C = Base S
3 rngimrcl ⊢ F ∈ R RngIso S → R ∈ V ∧ S ∈ V
4 1 2 isrngim2 ⊢ R ∈ V ∧ S ∈ V → F ∈ R RngIso S ↔ F ∈ R RngHom S ∧ F : B ⟶ 1-1 onto C
5 simpl ⊢ F ∈ R RngHom S ∧ F : B ⟶ 1-1 onto C → F ∈ R RngHom S
6 4 5 biimtrdi ⊢ R ∈ V ∧ S ∈ V → F ∈ R RngIso S → F ∈ R RngHom S
7 3 6 mpcom ⊢ F ∈ R RngIso S → F ∈ R RngHom S