Metamath Proof Explorer


Theorem rnssi

Description: Subclass inference for range. (Contributed by Peter Mazsa, 24-Sep-2022)

Ref Expression
Hypothesis rnssi.1 ⊢ A ⊆ B
Assertion rnssi ⊢ ran ⁡ A ⊆ ran ⁡ B

Proof

Step Hyp Ref Expression
1 rnssi.1 ⊢ A ⊆ B
2 rnss ⊢ A ⊆ B → ran ⁡ A ⊆ ran ⁡ B
3 1 2 ax-mp ⊢ ran ⁡ A ⊆ ran ⁡ B