Theorem rnssi

Description: Subclass inference for range. (Contributed by Peter Mazsa, 24-Sep-2022)

	Ref	Expression
Hypothesis	rnssi.1	⊢ 𝐴 ⊆ 𝐵
Assertion	rnssi	⊢ ran 𝐴 ⊆ ran 𝐵

Proof

Step	Hyp	Ref	Expression
1		rnssi.1	⊢ 𝐴 ⊆ 𝐵
2		rnss	⊢ ( 𝐴 ⊆ 𝐵 → ran 𝐴 ⊆ ran 𝐵 )
3	1 2	ax-mp	⊢ ran 𝐴 ⊆ ran 𝐵